"Calculating the Molar Mass of Magnesium Fluoride"

If you want to know the molar mass of $MgF_ {2} $, you need to know the relative atomic mass of each element. For magnesium ($Mg $), the relative atomic mass is about 24 dollars $; for fluorine ($F $), the relative atomic mass is about 19 dollars $.

$MgF_ {2} $consists of a magnesium atom and a difluorine atom. Therefore, its molar mass is the sum of the molar mass of the magnesium atom and the molar mass of the difluorine atom.

That is, $MgF_ {2} $molar mass $M = 24 + 2 × 19 $
$= 24 + 38 $
$= 62g/mol $.

From this, the molar mass of $MgF_ {2} $is $62g/mol $, which is an important basis for accurately calculating stoichiometry and related reaction amounts.